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1.The average marks obtained by 120 cndidates in a certain examinationis 35.if the average marks of passed candidate is 39 and that of the failed candidates is 15,what is the number of candidates who passed the examination?
110
100

120

115

None of these

(b)
Let No. of passed candidates are x
So, x * 39 + (120 – x) 15= 120 * 35 x = 100
So, x * 39 + (120 – x) 15= 120 * 35 x = 100
2.The average age of 8 persons in a committee is increased by 2 years when two men aged 35 years and 45 years are substituted by two women.Find the average age of these two women.
48
36

42

29

None of these

(a) Total increase = 8 * 2 = 16 years
So,
total age of two women = 35 + 45 +16= 96
Average age of two women=96/2=48 years
total age of two women = 35 + 45 +16= 96
Average age of two women=96/2=48 years
3.In a class, there are 20 boys whose average age is decreased by 2 months, when one boy aged 18 years is replaced by a new boy.Find the age of new boy.
19 years
14 years 6 month

15 years

14 years 8 month

12 years

(d) Total decrease = 20 * 2 = 40 month
= 3 years 4 month
So, age of new boy = 18 years – 3 years 4 month
= 14 years 8 month
So, age of new boy = 18 years – 3 years 4 month
= 14 years 8 month
4.One -third of certain journey is covered at the rate of 25kmph,one-fourth at the rate of 30kmph and the rest at 50 kmph.Find the average speed for the whole journey.
33.33 kmph
36

42

27

none of these

(a) Average speed = total distance / total time
LCM = 3, 4 = 12
Average speed = 12 / (1/3*12*1/25 + ¼ * 12*1/30 +5/50)
= 12/ (4/25 + 3/30+ 5/30
= 150*12/54 = 33.333 kmph
LCM = 3, 4 = 12
Average speed = 12 / (1/3*12*1/25 + ¼ * 12*1/30 +5/50)
= 12/ (4/25 + 3/30+ 5/30
= 150*12/54 = 33.333 kmph
5.The average salary of the entire staff in a office is Rs 120 per month.The average salary of officers is Rs 460 and of non officers is Rs 110. If the number of officers is 15,then find the No of non-officers in the office.
480
500

600

430

510

(e) Let no. of non- officers be x
15 * 460 + x * 110 = (x + 15) 120
x = 510
15 * 460 + x * 110 = (x + 15) 120
x = 510
6. There were 35 students in a hostel.If the number of students increased by 7, the expenses of the mess increases by Rs. 42 per day,while the average expenditure per head diminishes by Rs.1.Find the original expenditure of the mess.
420
400

480

460

None of these

(a) Let average expenditure per head be = x
So, (35 + 7) (x -1) – 35 x = 42
42 (x -1) – 35x = 42
X =12
Original expenditure of mess = 12 * 35 = 420
So, (35 + 7) (x -1) – 35 x = 42
42 (x -1) – 35x = 42
X =12
Original expenditure of mess = 12 * 35 = 420
7.The average weight of A,B,and C is 84 kg. If D joins the group, the average weight of the group becomes 80 kg.If another man E who weights is 3 kg more than D Replaces A, Then the average of B,C,Dand E becomes 79 kg. What is the weight of A?
64
72

75

100

80

(c) A + B + C = 3 *84 = 252
A + B + C + D = 4 * 80 = 320 ---- (i)
So, D = 68& E = 68 + 3 = 71 B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii) A-E = 320 – 316 = 4 A = E +4 = 71 + 4 = 75
So, D = 68& E = 68 + 3 = 71 B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii) A-E = 320 – 316 = 4 A = E +4 = 71 + 4 = 75
8.In an exam, the average was found to be 50 marks. After deducting computational errors the marks of the 100 candidates had to be changed from 90 to 60 each and average came down to 45 marks. Total No of candidates who took the exam were.
300
600

200

150

None of these

(b) Let the total no. of candidates = x
So, (50x-100 (90-60)) / x = 45
x = 600
So, (50x-100 (90-60)) / x = 45
x = 600
9.Find the average of all even No's up to 100 or average of first 50 even No's.
50
50.5

51

49

None of these

(c) 2, 4, 6, ………… 100
Average = (1st No. + Last No.) /2 = (2+100)/2 = 51
Average = (1st No. + Last No.) /2 = (2+100)/2 = 51
10.The average of 8 No's is 20. The average of first two No's is 15.5 and that of next three No's is 64/3.if the 6th No be less than the seventh and eight No. by 4 and 7 respectively, then find eight No.
26
25.5

27

25

None of these

(c) Total Sum of 8 nos. = 20 * 8 = 160
Sum of 1st two nos. = 2 * 15.5 = 31
Sum of next three nos. = 3 * 64/3 = 64
Let 6th no. be x 31 + 64 + x + (x+4) + (x+7) = 160
x = 18
8th no. = 18 + 7 = 25
Sum of 1st two nos. = 2 * 15.5 = 31
Sum of next three nos. = 3 * 64/3 = 64
Let 6th no. be x 31 + 64 + x + (x+4) + (x+7) = 160
x = 18
8th no. = 18 + 7 = 25
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